(x+2)(x+3)=x^2-9

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Solution for (x+2)(x+3)=x^2-9 equation:


Simplifying
(x + 2)(x + 3) = x2 + -9

Reorder the terms:
(2 + x)(x + 3) = x2 + -9

Reorder the terms:
(2 + x)(3 + x) = x2 + -9

Multiply (2 + x) * (3 + x)
(2(3 + x) + x(3 + x)) = x2 + -9
((3 * 2 + x * 2) + x(3 + x)) = x2 + -9
((6 + 2x) + x(3 + x)) = x2 + -9
(6 + 2x + (3 * x + x * x)) = x2 + -9
(6 + 2x + (3x + x2)) = x2 + -9

Combine like terms: 2x + 3x = 5x
(6 + 5x + x2) = x2 + -9

Reorder the terms:
6 + 5x + x2 = -9 + x2

Add '-1x2' to each side of the equation.
6 + 5x + x2 + -1x2 = -9 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
6 + 5x + 0 = -9 + x2 + -1x2
6 + 5x = -9 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
6 + 5x = -9 + 0
6 + 5x = -9

Solving
6 + 5x = -9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 5x = -9 + -6

Combine like terms: 6 + -6 = 0
0 + 5x = -9 + -6
5x = -9 + -6

Combine like terms: -9 + -6 = -15
5x = -15

Divide each side by '5'.
x = -3

Simplifying
x = -3

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